Kinetic Theory Of Gases Question 75
Question: Two gases occupy two containers A and B the gas in A, of volume $ 0.10m^{3} $ , exerts a pressure of 1.40 MPa and that in B of volume $ 0.15m^{3} $ exerts a pressure 0.7 MPa. The two containers are united by a tube of negligible volume and the gases are allowed to intermingle. Then if the temperature remains constant, the final pressure in the container will be (in MPa)
Options:
A) 0.70
B) 0.98
C) 1.40
D) 210
Show Answer
Answer:
Correct Answer: B
Solution:
[b] We know that $ P _{A}V _{A}=nRT,P _{B}V _{B}=n _{B}RT $ and
$ P _{f}(V _{A}+V _{B})=(n _{A}+n _{B})RT $
$ P _{f}(V _{A}+V _{B})=P _{A}V _{A}+P _{B}V _{B} $
$ \
Therefore P _{f}=( \frac{P _{A}V _{A}+P _{B}V _{B}}{V _{A}+V _{B}} ) $
$ =\frac{1.4\times 0.1+0.7\times 0.15}{0.1+0.15}MPa $
$ =0.98MPa $
BETA
