Kinetic Theory Of Gases Question 77
Question: The equation of state of a gas is given by $ ( P+\frac{aT^{2}}{V} )V^{c}=( RT+b ) $ where a, b, c and R are constants. The isotherms can be represented $ P=AV^{m}-BV^{n}, $ where A and 5 depend only on temperature and
Options:
A) $ m=-c\text{ and }n=-1 $
B) $ m=c\text{ and }n=-1 $
C) $ m=-c\text{ and }n=1 $
D) $ m=c\text{ and }n=-1 $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ ( P+\frac{aT^{2}}{V} )V^{c}=( RT+b ) $
$ \Rightarrow P=(RT+b){{V}^{-c}}-(aT^{2}){{V}^{-1}} $ On comparing with equation, $ P=AV^{m}-BV^{n},m=-c\text{ and }n=-1. $
BETA
