Kinetic Theory Of Gases Question 93
Question: At very high temperatures vibrational degrees also becomes active. At such temperatures an ideal diatomic gas has a molar specific heat at constant pressure, $ C _{p} $ is
Options:
A) 3R/2
B) 5R/2
C) 6R/2
D) 9R/2
Show Answer
Answer:
Correct Answer: D
Solution:
[d] At high temperature for diatomic gas $ f=7 $
$ C _{p}=\frac{fR}{2}+R=\frac{9R}{2} $
BETA
