Kinetic Theory Of Gases Question 96
Question: One mole of a gas occupies 22.4 lit at N.T.P. Calculate the difference between two molar specific heats of the gas. $ J=4200J/kcal. $
Options:
A) 1.979kcal/k mol K
B) 2.378 kcal/k mol K
C) 4.569 kcal/k mol K
D) 3.028 kcal/k mol K
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ V=22.4litre=22.4\times {{10}^{-3}}m^{3},J=4500J/kcal $ By ideal gas equation for one mole of a gas, $ R=\frac{PV}{T}=\frac{1.013\times 10^{5}\times 22.4\times {{10}^{-3}}}{273} $
$ C _{p}-C _{v}=\frac{R}{J}=\frac{1.013\times 10^{5}\times 22.4}{273\times 4200}=1.979 $ kcal/kmol K
BETA
