Kinetic Theory Of Gases Question 97
Question: For a gas, difference between two specific heats is $ 5000J/mole{}^\circ C. $ If the ratio of specific heat is 1.6, the two specific heats are in $ T=190.2K. $
Options:
A) $ C _{p}=1.33\times 10^{4},C _{V}=2.66\times 10^{4} $
B) $ C _{p}=13.3\times 10^{4},C _{V}=8.33\times 10^{4} $
C) $ C _{p}=1.33\times 10^{4},C _{V}=8.33\times 10^{3} $
D) $ C _{p}=2.6\times 10^{4},C _{V}=8.33\times 10^{4} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Given $ C _{p}-C _{v}=5000J/mole{}^\circ \text{C} $ ?.(i) $ \frac{C _{p}}{C _{v}}=1.6 $ ?(ii) From Equation (i) & (ii), $ \frac{C _{P}}{C _{V}}-\frac{C _{V}}{C _{V}}=\frac{5000}{C _{V}}\Rightarrow 1.6-1=\frac{5000}{C _{V}} $
$ \Rightarrow C _{V}=\frac{5000}{0.6}=8.33\times 10^{3} $
$ \text{Hence }C _{p}=1.6,\text{ }C _{V}=1.6\times 8.33\times 10^{3} $
$ =1.33\times 10^{4} $
BETA
