Kinetic Theory Of Gases Question 116
Question: The average kinetic energy of a gas at $ 23{}^\circ C $ and 75 cm pressure is $ 5\times {{10}^{-14}},erg $ for $ H _{2} $ . The mean kinetic energy of the $ O _{2} $ at $ 227{}^\circ C $ and 150 cm pressure will be
Options:
A) $ 80\times {{10}^{-14}},erg $
B) $ 20\times {{10}^{-14}},erg $
C) $ 40\times {{10}^{-14}},erg $
D) $ 10\times {{10}^{-14}},erg $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Average kinetic energy $ E=\frac{3}{2}kT $
Therefore $ \frac{E _{1}}{E _{2}}=\frac{T _{1}}{T _{2}}=\frac{(273-23)}{(273+227)}=\frac{250}{500}=\frac{1}{2} $
Therefore $ E _{2}=2E _{1}=2\times 5\times {{10}^{-14}}=10\times {{10}^{-14}},erg $
BETA
