Kinetic Theory Of Gases Question 38

Question: At what temperature is the r. m. s velocity of a hydrogen molecule equal to that of an oxygen molecule at $ 47{}^\circ C $ ?

Options:

A) 80 K

B) -73 K

C) 3 K

D) 20 K

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $ v _{rms}=\sqrt{\frac{8RT}{\pi M}} $ For $ v _{rms} $ to be equal $ \frac{{T _{H _{2}}}}{{M _{H _{2}}}}=\frac{TO _{2}}{MO _{2}} $ Here $ {M _{H _{2}}}=2;{M _{O _{2}}}=32; $

$ {T _{O _{2}}}=47+273=320K $
$ \

Therefore \frac{{T _{H _{2}}}}{2}=\frac{320}{32}\Rightarrow {T _{H _{2}}}=20K $