Kinetic Theory Of Gases Question 38
Question: At what temperature is the r. m. s velocity of a hydrogen molecule equal to that of an oxygen molecule at $ 47{}^\circ C $ ?
Options:
A) 80 K
B) -73 K
C) 3 K
D) 20 K
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ v _{rms}=\sqrt{\frac{8RT}{\pi M}} $ For $ v _{rms} $ to be equal $ \frac{{T _{H _{2}}}}{{M _{H _{2}}}}=\frac{TO _{2}}{MO _{2}} $ Here $ {M _{H _{2}}}=2;{M _{O _{2}}}=32; $
$ {T _{O _{2}}}=47+273=320K $
$ \
Therefore \frac{{T _{H _{2}}}}{2}=\frac{320}{32}\Rightarrow {T _{H _{2}}}=20K $