Kinetic Theory Of Gases Question 120
Question: The kinetic energy of one mole gas at 300K temperature, is E. At 400K temperature kinetic energy is $ {E}’. $ The value of $ {E}’/E $ is
Options:
A) 1.33
B) $ \sqrt{( \frac{4}{3} )} $
C) $ \frac{16}{9} $
D) 2
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ E=\frac{3}{2}RT $
Therefore $ \frac{{{E}’}}{E}=\frac{{{T}’}}{T}=\frac{400}{300}=\frac{4}{3}=1.33 $
BETA
