Kinetic Theory Of Gases Question 100
Question: The K.E. of one mole of an ideal gas is E=(3/2) RT. Then $ C _{p} $ will be
Options:
A) 0.5 R
B) 0.1 R
C) 1.5 R
D) 2.5 R
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ C _{v}=dE/dT=\frac{3}{2}R $
$ C _{p}=\frac{3}{2}R+R=\frac{5}{2}R=2.5R $