Kinetic Theory Of Gases Question 100

Question: The K.E. of one mole of an ideal gas is E=(3/2) RT. Then $ C _{p} $ will be

Options:

A) 0.5 R

B) 0.1 R

C) 1.5 R

D) 2.5 R

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $ C _{v}=dE/dT=\frac{3}{2}R $

$ C _{p}=\frac{3}{2}R+R=\frac{5}{2}R=2.5R $