Kinetic Theory Of Gases Question 125
Question: The value of PV/T for one mole of an ideal gas is nearly equal to
Options:
A) $ 2Jmol^{1}K^{1} $
B) $ 8.3calmol^{1}K^{1} $
C) $ 4.2Jmol^{1}K^{1} $
D) $ 2calmol^{1}K^{1} $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ PV=RT $
Therefore $ \frac{PV}{T}=R\approx 2\frac{cal}{mol\text{-}K}. $
BETA
