Laws Of Motion Question 195
Question: A body of mass 4 kg weighs 4.8 kg when suspended in a moving lift. The acceleration of the lift is [Manipal MEE 1995]
Options:
A) $ 9.80m{{s}^{-2}} $ downwards
B) 9.80$ m{{s}^{-2}} $ upwards
C) 1.96$ m{{s}^{-2}} $ downwards
D) 1.96$ m{{s}^{-2}} $ upwards
Show Answer
Answer:
Correct Answer: D
Solution:
As the apparent weight increase therefore we can say that acceleration of the lift is in upward direction. $ R=m(g+a) $ therefore$ 4.8\ g=4(g+a) $ therefore$ a=0.2g=1.96\ m/s^{2} $
BETA
