Laws Of Motion Question 278
Question: A particle of mass 0.3 kg subject to a force $ F=-kx $ with$ k=15N/m $ . What will be its initial acceleration if it is released from a point 20 cm away from the origin?
Options:
A) $ 15m/s^{2} $
B) $ 3m/s^{2} $
C) $ 10m/s^{2} $
D) $ 5m/s^{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ Mass( m )=0.3kg\Rightarrow F=m.a=-15x $
$ a=-\frac{15}{0.3}x=\frac{-150}{3}x=-50x $
$ a=-50\times 0.2=10\text{ m/}{{m}^{2}} $
BETA
