Laws Of Motion Question 116
Question: A body of weight 64 N is pushed with just enough force to start it moving across a horizontal floor and the same force continues to act afterwards.If the coefficients of static and dynamic friction are 0.6 and 0.4 respectively, the acceleration of the body will be (Acceleration due to gravity = g) [EAMCET 2001]
Options:
A) $ \frac{g}{6.4} $
B) 0.64 g
C) $ \frac{g}{32} $
D) 0.2 g
Show Answer
Answer:
Correct Answer: D
Solution:
Weight of the body = 64N so mass of the body
$ m=6.4\ kg $ ,$ {{\mu } _{s}}=0.6 $ ,
$ {{\mu } _{k}}=0.4 $ Net acceleration $ =\frac{\text{Applied force -Kinetic friction}}{\text{Mass of the body}} $
$ =\frac{{{\mu } _{s}}mg-{{\mu } _{k}}mg}{m}=({{\mu } _{s}}-{{\mu } _{k}})g=(0.6-0.4)g=0.2g $
BETA
