Laws Of Motion Question 287
A ball of mass 10 g moving perpendicular to the plane of the wall strikes it and rebounds in the opposite line with the same speed. If the impulse experienced by the wall is 0.54 Ns, the velocity of the ball is
Options:
A) $ 27m{{s}^{-1}} $
B) $ 3.7m{{s}^{-1}} $
C) $ 54m{{s}^{-1}} $
D) $ 37m{{s}^{-1}} $
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Answer:
Correct Answer: A
Solution:
[a] As the ball, $ m=10\text{ }g=0.01\text{ }kg$
rebounds after striking the wall
$\therefore $ Change in momentum $=mv-(-mv)=2\text{ }mv $
Impulse = Change in momentum $=~mv$
$\therefore v=\frac{\text{Impulse}}{2m}=\frac{0.54\text{ N s}}{2\times 0.01\text{ kg}}=24\text{ m}{{\text{s}}^{-1}}$
$
BETA
