Laws Of Motion Question 117
Question: A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction m = 0.5.If a horizontal force of 100 N is acting on it, then acceleration of the block will be [AIIMS 2002]
Options:
A) $ 0.5m/s^{2} $
B) $ 5m/s^{2} $
C) $ 10m/s^{2} $
D) $ 15m/s^{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ a=\frac{\text{Applied force –Kinetic friction}}{m} $
$ =\frac{100-0.5\times 10\times 10}{10}=5m/s^{2} $
BETA
