Laws Of Motion Question 315
Two blocks $ m _{1}=5\text{ gm} $ and$ m _{2}=\text{gm} $ are hung vertically over a light frictionless pulley as shown here. What is the acceleration of the masses when they are left free? (Where g is acceleration due to gravity)
Options:
A) $ g/3 $
B) $ g/2 $
C) $ g $
D) $\frac{g}{5}$
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Answer:
Correct Answer: A
Solution:
[a] Let T be the tension in the string.
$ \therefore 10g-T=10a …(i)$
$ T-5g=5a\quad\text{(ii)} $
Adding (i) and (ii), $5g=15a\Rightarrow a=\frac{g}{3}m/s^{2}$
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