Laws Of Motion Question 323
Question: Two blocks of mass $ M _{1}=20kg $ and $ M _{2}=12kg $ are connected by a metal rod of mass 8 kg. The system is pulled vertically up by applying a force of 480 N as shown. The tension at the mid-point of the rod is:
Options:
A) 144 N
B) 96 N
C) 240 N
D) 192 N
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Acceleration produced in upward direction
$ a=\frac{F}{M _{1}+M _{2}+\text{Mass of metal rod}} $
=$ \frac{480}{20+12+8}=12\text{ m}{{s}^{-2}} $
Tensions at the mid-point $ T=( M _{2}+\frac{\text{Mass of rod}}{2} )a $
$ =( 12+4 )\times 12=192N $
BETA
