Laws Of Motion Question 331
Question: A small mass slides down a fixed inclined plane of inclination 6 with the horizontal. The coefficient of friction is $ \mu ={{\mu } _{0}}x $ Where $ x $ is the distance through which the mass slides down and $ {{\mu } _{0}} $ is a constant? Then he speed is maximum after the mass covers a distance of
Options:
A) $ \frac{\cos \theta }{{{\mu } _{0}}} $
B) $ \frac{\sin \theta }{{{\mu } _{0}}} $
C) $ \frac{tan\theta }{{{\mu } _{0}}} $
D) $ \frac{2tan\theta }{{{\mu } _{0}}} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Acceleration of mass at distance x
$ a=g(\sin \theta -{{\mu } _{0}}x\cos \theta ) $
Speed is maximum, when $ a=0 $
$ g( sin\theta -{{\mu } _{0}}xcos\theta)=0 $
$ x=\frac{\tan \theta }{{{\mu } _{0}}} $
BETA
