Laws Of Motion Question 121
Question: A body of mass 5kg rests on a rough horizontal surface of coefficient of friction 0.2.The body is pulled through a distance of 10m by a horizontal force of 25 N.The kinetic energy acquired by it is (g = 10 ms2) [EAMCET (Med.) 2000]
Options:
A) 330 J
B) 150 J
C) 100 J
D) 50 J
Show Answer
Answer:
Correct Answer: B
Solution:
Kinetic energy acquired by body = (Total work done on the body) ? (work against friction)$ =F\times S-\mu mgS=25\times 10-0.2\times 5\times 10\times 10 $
$ =250-100=150\ Joule $
BETA
