Laws Of Motion Question 200
Question: The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ?a? is 3 : 2. The value of ?a? is (g-Acceleration due to gravity of the earth) [MP PET 1997]
Options:
A) $ \frac{3}{2}g $
B) $ \frac{g}{3} $
C) $ \frac{2}{3}g $
D) g
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{mg}{m(g-a)}=\frac{3}{2} $
therefore $ a=g/3 $
BETA
