Laws Of Motion Question 36
Question: A 100 g iron ball having velocity 10 m/s collides with a wall at an angle 30° and rebounds with the same angle. If the period of contact between the ball and wall is 0.1 second, then the force experienced by the wall is[CPMT 1997]
Options:
A)10 N
B) 100 N
C) 1.0 N
D) 0.1 N
Show Answer
Answer:
Correct Answer: A
Solution:
During collision of ball with the wall horizontal momentum changes (vertical momentum remains constant) $ \therefore $ $ F=\frac{\text{Change in horizontal momentum }}{\text{Time of contact}} $
$ =\frac{2P\cos \theta }{0.1}=\frac{2mv\cos \theta }{0.1} $
$ =\frac{2\times 0.1\times 10\times \cos 60{}^\circ }{0.1} $
$ =10\ N $
BETA
