Laws Of Motion Question 204
Question: A mass 1 kg is suspended by a thread. It is (i) lifted up with an acceleration $ 4.9m/s^{2} $ (ii) lowered with an acceleration $ 4.9m/s^{2} $ . The ratio of the tensions is [CBSE PMT 1998]
Options:
A) 3 : 1
B) 1 : 3
C) 1 : 2
D) 2 : 1
Show Answer
Answer:
Correct Answer: A
Solution:
$ T _{1}=m(g+a)=1\times ( g+\frac{g}{2} )=\frac{3g}{2} $
$ T _{2}=m(g-a)=1\times ( g-\frac{g}{2} )=\frac{g}{2} $ $ \frac{T _{1}}{T _{2}}=\frac{3}{1} $
BETA
