Laws Of Motion Question 383
Question: In the above ques., the height to which the lift takes the passenger is
Options:
A) 3.6 meters
B) 8 meters
C) 1.8 meters
D) 36 meters
Show Answer
Answer:
Correct Answer: D
Solution:
Distance travelled by the lift $ = $ Area under velocity time graph $ =( \frac{1}{2}\times 2\times 3.6 )+( 8\times 3.6 )+( \frac{1}{2}\times 2\times 3.6 ) $ = $ 36m $
BETA
