Laws Of Motion Question 394
Question: Car is accelerating with acceleration = 20 m/s2. A box of mass m = 10 kg that is placed inside the car it is put in contact with the vertical wall of car as shown. The friction coefficient between the box and the wall is $ \mu =0.6 $ .
Options:
A) The acceleration of the box will be $ 10,m/{{\sec }^{2}} $
B) The friction force acting on the box will be 100 N
C) The contact force between the vertical wall and the box will be 100 N
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
The breaking force is insufficient, so the block will not slide.
So friction force = 100 N
and acceleration will be $ 20m/{{\sec }^{2}} $ only
Net contact force on the block
$ =\sqrt{{{( 200 )}^{2}}+{{( 100 )}^{2}}}=100\sqrt{5}N $
BETA
