Laws Of Motion Question 401
Question: Mass of block A is 10 kg. Coefficient of friction between the block A and surface is 0.3. What is the maximum values of M for which system remains in equilibrium$ ( g=10m/s^{2} ) $
Options:
A) 2 kg
B) 6 kg
C) 3 kg
D) 5 kg
Show Answer
Answer:
Correct Answer: C
Solution:
Maximum friction force between block A and surface is:
$ {f _{ _{\max }}}=\mu mg=( 0.3 )( 10 )( 10 )=30N $
Therefore, maximum tension in the string connected with block A should be 30 N.
Now,
$ T’\cos 45{}^\circ =30 $ …(1)
$ T’sin45{}^\circ =Mg $ ….(2)
From equations (1) and (2), M = 3 kg
BETA
