Laws Of Motion Question 42
Question: A man fires a bullet of mass 200 g at a speed of 5 m/s. The gun is of one kg mass. by what velocity the gun rebounds backwards [CBSE PMT 1996; JIPMER 2000]
Options:
A) 0.1 m/s
B) 10 m/s
C) 1 m/s
D) 0.01 m/s
Show Answer
Answer:
Correct Answer: C
Solution:
$ v _{G}=\frac{m _{B}v _{B}}{m _{G}}=\frac{0.2\times 5}{1}=1\ m/s $
BETA
