Laws Of Motion Question 427
Question: Two particles A and B are connected by a rigid rod AB. The rod slides along perpendicular rails as shown here. The velocity of A to the left is 10 m/s. What is the speed of B when angle $ \theta =45^{o}? $
Options:
A) 5 m/s
B) (b)$ 5\sqrt{2}m/s $
C) 10 m/s
D) 7.5 m/s
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ x^{2}+y^{2}=l^{2} $
$ 2x\frac{dx}{dt}+2y\frac{dy}{dt}=0 $
$ \Rightarrow $ $ {{\upsilon } _{b}}=\frac{dx}{dt}=10m/s $
$ (x=yat45^{\circ}) $
BETA
