Laws Of Motion Question 44
Question: A force of 50 dynes is acted on a body of mass 5 g which is at rest for an interval of 3 seconds, then impulse is [AFMC 1998]
Options:
A) $ 0.15\times {{10}^{-3}}Ns $
B) $ 0.98\times {{10}^{-3}}Ns $
C) $ 1.5\times {{10}^{-3}}Ns $
D) $ 2.5\times {{10}^{-3}}Ns $
Show Answer
Answer:
Correct Answer: C
Solution:
Impulse, $ I=F\times \Delta t=50\times {{10}^{-5}}\times 3 $ =$ 1.5\times {{10}^{-3}}\ N\text{-}s $
BETA
