Laws Of Motion Question 48
Question: A bullet of mass 0.1 kg is fired with a speed of 100 m/sec, the mass of gun is 50 kg. The velocity of recoil is [AFMC 1995; JIPMER 2000; Pb.PMT 2002]
Options:
A) 0.2 m/sec
B) 0.1 m/sec
C) 0.5 m/sec
D) 0.05 m/sec
Show Answer
Answer:
Correct Answer: A
Solution:
According to principle of conservation of linear momentum, $ m _{G}v _{G}=m _{B}v _{B} $
$ \Rightarrow $ $ v _{G}=\frac{m _{B}v _{B}}{m _{G}}=\frac{0.1\times 10^{2}}{50}=0.2m/s $
BETA
