Laws Of Motion Question 61
Question: A ship of mass $ 3\times 10^{7}kg $ initially at rest is pulled by a force of $ 5\times 10^{4}N $ through a distance of 3 m. Assume that the resistance due to water is negligible, the speed of the ship is [IIT 1980; MP PMT 2000]
Options:
A) 1.5 m/s
B) 60 m/s
C) 0.1 m/s
D) 5 m/s
Show Answer
Answer:
Correct Answer: C
Solution:
$ v^{2}=2as=2( \frac{F}{m} )\ s $
$ [As\ u=0] $
therefore $ v^{2}=2( \frac{5\times 10^{4}}{3\times 10^{7}} )\times 3=\frac{1}{100} $
therefore $ v=0.1\ m/s $
BETA
