Laws Of Motion Question 72
Question: One day on a spacecraft corresponds to 2 days on the earth. The speed of the spacecraft relative to the earth is[CBSE PMT 1993]
Options:
A) $ 1.5\times 10^{8}m{{s}^{-1}} $
B) $ 2.1\times 10^{8}m{{s}^{-1}} $
C) $ 2.6\times 10^{8}m{{s}^{-1}} $
D) $ 5.2\times 10^{8}m{{s}^{-1}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ T=\frac{T _{0}}{{{[1-(v^{2}/c^{2})]}^{1/2}}} $ By substituting $ T _{0}= $ 1 day and $ T= $ 2 days we get $ v=2.6\times 10^{8}m{{s}^{-1}} $
BETA
