Laws Of Motion Question 85
Question: Two blocks are connected by a string as shown in the diagram. The upper block is hung by another string. A force F applied on the upper string produces an acceleration of $ 2m/s^{2} $ in the upward direction in both the blocks. If T and $ {T}’ $ be the tensions in the two parts of the string, then [AMU (Engg.) 2000]
Options:
A) $ T=70.8N $ and $ {T}’=47.2N $
B) $ T=58.8N $ and $ {T}’=47.2N $
C) $ T=70.8N $ and $ {T}’=58.8N $
D) $ T=70.8N $ and $ {T}’=0 $
Show Answer
Answer:
Correct Answer: A
Solution:
FBD of mass 2 kg FBD of mass 4kg $ T-{T}’-20=4a $ ..(i)
$ {T}’-40=8 $ -(ii)
By solving (i) and (ii) $ T’=47.23,N $ and $ T=70.8,N $
BETA
