Laws Of Motion Question 87
Question: A block is kept on a frictionless inclined surface with angle of inclination ‘a’. The incline is given an acceleration ‘a’ to keep the block stationary. Then a is equal to [AIEEE 2005]
Options:
A) $ g $
B) $ gtan\alpha $
C) $ g/tan\alpha $
D) $ gcosec\alpha $
Show Answer
Answer:
Correct Answer: B
Solution:
Let the mass of a block is m. It will remains stationary if forces acting on it are in equilibrium i.e, $ ma\cos \alpha =mg\sin \alpha $
therefore $ a=g\tan \alpha $
Here $ ma $ = Pseudo force on block, mg = Weight.
BETA
