Laws Of Motion Question 158

Question: A 2 kg block is lying on a smooth table which is connected by a body of mass 1 kg by a string which passes through a pulley. The 1 kg mass is hanging vertically. The acceleration of block and tension in the string will be [RPMT 1997]

Options:

A) $ 3.27m/s^{2},6.54N $

B) $ 4.38m/s^{2},6.54N $

C) $ 3.27m/s^{2},9.86N $

D) $ 4.38m/s^{2},9.86N $

Show Answer

Answer:

Correct Answer: A

Solution:

Acceleration$ =\frac{m _{2}}{m _{1}+m _{2}}\times g $

$ =\frac{1}{2+1}\times 9.8=3.27\ m/s^{2} $ and $ T=m _{1}a=2\times 3.27=6.54\ N $



sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
कृपया अपनी पसंदीदा भाषा चुनें