Laws Of Motion Question 171
Question: A diwali rocket is ejecting 0.05 kg of gases per second at a velocity of 400 m/sec. The accelerating force on the rocket is [NCERT 1979; DPMT 2001; MP PMT 2004]
Options:
A)20 dynes
B) 20 N
C) 22 dynes
D) 1000 N
Show Answer
Answer:
Correct Answer: B
Solution:
$ F=u( \frac{dm}{dt} )=400\times 0.05=20\ N $
BETA
