Laws Of Motion Question 188
Question: A particle of mass 0.3 kg is subjected to a force $ F=-kx $ with $ k=15N/m. $ What will be its initial acceleration if it is released from a point 20 cm away from the origin [AIEEE 2005]
Options:
A) 5 m/s2
B) 10 m/s2
C) 3 m/s2
D) 15 m/s2
Show Answer
Answer:
Correct Answer: B
Solution:
Force on particle at 20 cm away $ F=kx $ F = 15 × 0.2 = 3 N $ [ \text{As }k=15\ N/m ] $
$ \therefore $ Acceleration = $ \frac{Force}{Mass}=\frac{3}{0.3}=10m/s^{2} $
BETA
