Laws Of Motion Question 226
Question: A 30 gm bullet initially travelling at 120 m/s penetrates 12 cm into a wooden block. The average resistance exerted by the wooden block is [AFMC 1999; CPMT 2001]
Options:
A) 2850N
B) 2200 N
C) 2000N
D) 1800 N
Show Answer
Answer:
Correct Answer: D
Solution:
$ F=\frac{m(u^{2}-v^{2})}{2S}=\frac{30\times {{10}^{-3}}\times {{(120)}^{2}}}{2\times 12\times {{10}^{-2}}}=1800N $
BETA
