Laws Of Motion Question 230
If the rope of a lift breaks suddenly, the tension exerted by the surface of the lift [AFMC 2002] (a = acceleration of lift)
Options:
mg
B) $ m(g+a) $
C) $ m(g-a) $
D) $ 0 $
Show Answer
Answer:
Correct Answer: D
Solution:
If the rope of a lift breaks suddenly, acceleration becomes equal to g so that tension, $ T=m(g-a)=0 $
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