Laws Of Motion Question 237
Question: A man weighs $ 80kg. $ He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $ 5m/s^{2}. $ What would be the reading on the scale. $ (g=10m/s^{2}) $ [CBSE PMT 2003]
Options:
A) 400 N
B) 800 N
C) 1200 N
D) Zero
Show Answer
Answer:
Correct Answer: C
Solution:
For accelerated upward motion $ R=m(g+a)=80(10+5)=1200N $
BETA
