Laws Of Motion Question 247
Question: A man of weight 75 kg is standing in an elevator which is moving with an acceleration of $ 5m/s^{2} $ in upward direction the apparent weight of the man will be $ (g=10m/s^{2}) $ [Pb. PMT 2004]
Options:
A) 1425 N
B) 1375 N
C) 1250 N
D) 1125 N
Show Answer
Answer:
Correct Answer: D
Solution:
The apparent weight, $ R=m(g+a)=75(10+5)=1125N $
BETA
