Laws Of Motion Question 251
Question: A man of weight 80 kg is standing in an elevator which is moving with an acceleration of $ 6m/s^{2} $ in upward direction. The apparent weight of the man will be $ (g=10m/s^{2}) $ [DPMT 2003]
Options:
A) 1480 N
B) 1280 N
C) 1380 N
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
The apparent weight of man, $ R=m(g+a)=80(10+6)=1280N $
BETA
