Magnetic Effects Of Current Question 127
Question: Two concentric coils each of radius equal to $ 2\pi cm $ are placed at right angles to each other. 3 ampere and 4 ampere are the currents flowing in each coil respectively. The magnetic induction in $ Weber/m^{2} $ at the centre of the coils will be $ ({\mu_{0}}=4\pi \times {{10}^{-7}}Wb/A.m) $ [AIEEE 2005]
Options:
A) $ 5\times {{10}^{-5}} $
B) $ 7\times {{10}^{-5}} $
C) $ 12\times {{10}^{-5}} $
D) $ {{10}^{-5}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ B_{net}=\sqrt{B_{1}^{2}+B_{2}^{2}} $ $ =\frac{{\mu_{0}}}{4\pi }.\frac{2\pi }{r}\sqrt{i_{1}^{2}+i_{2}^{2}} $ $ ={{10}^{-7}}\times \frac{2\pi }{2\pi \times {{10}^{-2}}}\sqrt{{{(3)}^{2}}+{{(4)}^{2}}}=5\times {{10}^{-5}},wb/m^{2} $
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