Magnetic Effects Of Current Question 145

Question: A particle of mass m and charge q moves with a constant velocity v along the positive x direction. It enters a region containing a uniform magnetic field B directed along the negative z direction, extending from x = a to x = b. The minimum value of v required so that the particle can just enter the region $ x>b $ is [IIT-JEE (Screening) 2002]

Options:

A) $ qb,B/m $

B) $ q(b-a)B/m $

C) $ qa,B/m $

D) $ q(b+a)B/2m $

Show Answer

Answer:

Correct Answer: B

Solution:

In the figure, the z-axis points out of the paper, and the magnetic field is directed into the paper, existing in the region between PQ and RS. The particle moves in a circular path of radius r in the magnetic field. It can just enter the region x > b for $ r\ge (b-a) $ Now, $ r=\frac{mv}{qB}\ge (b-a) $ or $ v\ge \frac{q(b-a)B}{m} $

Þ $ {\nu_{\min }}=\frac{q(b-a)B}{m} $