Magnetic Effects Of Current Question 187
Question: Three long, straight and parallel wires carrying currents are arranged as shown in figure. The force experienced by 10 cm length of wire Q is [MP PET 1997]
Options:
A) $ 1.4\times {{10}^{-4}}N $ towards the right
B) $ 1.4\times {{10}^{-4}}N $ towards the left
C) $ 2.6\times {{10}^{-4}}N $ to the right
D) $ 2.6\times {{10}^{-4}}N $ to the left
Show Answer
Answer:
Correct Answer: A
Solution:
Force on wire Q due to wire P is $ F_{P}={{10}^{-7}}\times \frac{2\times 30\times 10}{0.1}\times 0.1 $ $ =6\times {{10}^{-5}}N $ (Towards left) Force on wire Q due to wire R is $ F_{R}={{10}^{-7}}\times \frac{2\times 20\times 10}{0.02}\times 0.1=20\times {{10}^{-5}}N $ (Towards right) Hence $ F_{net}=F_{R}-F_{P}=14\times {{10}^{-5}}N=1.4\times {{10}^{-4}}N $ (Towards right)
BETA
