Magnetic Effects Of Current Question 195
A triangular loop of side l carries a current I. It is placed in a magnetic field B such that the plane of the loop is perpendicular to B. The torque on the loop is [MP PET 2003]
Options:
A) Zero
IBl
C) $ \frac{\sqrt{3}}{2}Il^{2}B^{2} $
D) $ \frac{\sqrt{3}}{4}IBl^{2} $
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Answer:
Correct Answer: D
Solution:
Since θ = 90° Hence $ \tau =NIAB=1\times I\times ( \frac{\sqrt{3}}{4}l^{2} ),B $ $ =\frac{\sqrt{3}}{4}l^{2}B $
BETA
