Magnetic Effects Of Current Question 195
Question: A triangular loop of side l carries a current I. It is placed in a magnetic field B such that the plane of the loop is in the direction of B. The torque on the loop is [MP PET 2003]
Options:
A) Zero
B) IBl
C) $ \frac{\sqrt{3}}{2}Il^{2}B^{2} $
D) $ \frac{\sqrt{3}}{4}IBl^{2} $
Show Answer
Answer:
Correct Answer: D
Solution:
Since q = 90° Hence $ \tau =NIAB=1\times I\times ( \frac{\sqrt{3}}{4}l^{2} ),B $ $ =\frac{\sqrt{3}}{4}l^{2}B $
BETA
