Magnetic Effects Of Current Question 206
Question: What is the net force on the square coil [DCE 2000; RPMT 2000]
Options:
A) $ 25\times {{10}^{-7}}N $ moving towards wire
B) $ 25\times {{10}^{-7}}N $ moving away from wire
C) $ 35\times {{10}^{-7}}N $ moving towards wire
D) $ 35\times {{10}^{-7}}N $ moving away from wire
Show Answer
Answer:
Correct Answer: A
Solution:
Force on side BC and AD are equal but opposite so their net will be zero. But $ F_{AB}={{10}^{-7}}\times \frac{2\times 2\times 1}{2\times {{10}^{-2}}}\times 15\times {{10}^{-2}}=3\times {{10}^{-6}}N $ and $ F_{CD}={{10}^{-7}}\times \frac{2\times 2\times 1}{( 12\times {{10}^{-2}} )}\times 15\times {{10}^{-2}} $ $ =0.5\times {{10}^{-6}}N $
Þ $ ,F_{net}=F_{AB}-F_{CD} $ $ =2.5\times {{10}^{-6}}N $ $ =25\times {{10}^{-7}}N $ , towards the wire.
BETA
