Magnetic Effects Of Current Question 210
Question: Due to the flow of current in a circular loop of radius R, the magnetic induction produced at the centre of the loop is B. The magnetic moment of the loop is $ ({\mu_{0}}=\text{permeability},\text{constant)} $ [MP PET 2000]
Options:
A) $ BR^{3}/2\pi {\mu_{0}} $
B) $ 2\pi BR^{3}/{\mu_{0}} $
C) $ BR^{2}/2\pi {\mu_{0}} $
D) $ 2\pi BR^{2}/{\mu_{0}} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ B=\frac{{\mu_{0}}i}{2R}\Rightarrow i=\frac{B\times 2R}{{\mu_{0}}} $ Now, $ M=i\times A=i\pi R^{2}=\frac{B\times 2R}{{\mu_{0}}}\times \pi R^{2}=\frac{2\pi BR^{3}}{{\mu_{0}}} $
BETA
