Magnetic Effects Of Current Question 24
The magnetic field $ d\overrightarrow{B} $ due to a small current element $ d\overrightarrow{l} $ at a distance $ r $ and element carrying current $ i $ is, or Vector form of Biot-savart’s law is [CBSE PMT 1996; MP PET 2002; MP PMT 2000]
Options:
A) $ d\overrightarrow{B}=\frac{{\mu_{0}}}{4\pi }i,( \frac{d\overrightarrow{l,}\times \overrightarrow{r,}}{r^{2}} ) $
B) $ d\overrightarrow{B}=\frac{{\mu_{0}}}{4\pi }i,( \frac{d\overrightarrow{l,}\times \overrightarrow{r,}}{r^{2}} ) $
C) $ d\overrightarrow{B}=\frac{{\mu_{0}}}{4\pi }i,( \frac{d\overrightarrow{l,}\times \overrightarrow{r,}}{r^{2}} ) $
D) $ d\overrightarrow{B}=\frac{{\mu_{0}}}{4\pi }i,( \frac{d\overrightarrow{l,}\times \overrightarrow{r,}}{r^{3}} ) $
Show Answer
Answer:
Correct Answer: D
Solution:
$ dB=\frac{{\mu_{0}}}{4\pi }\cdot \frac{idl\sin \theta }{r^{2}} $
Þ $ d\overrightarrow{B}=\frac{{\mu_{0}}}{4\pi }\cdot \frac{i,(d\overrightarrow{l,}\times \overrightarrow{r,})}{r^{3}} $
BETA
