Magnetic Effects Of Current Question 241
Question: A dip needle lies initially in the magnetic meridian when it shows an angle of dip $ \theta $ at a place. The dip circle is rotated through an angle $ x $ in the horizontal plane and then it shows an angle of dip $ \theta ’ $ . Then $ \frac{\tan \theta ‘}{\tan \theta } $ is
Options:
A) $ \frac{1}{\cos x} $
B) $ \frac{1}{\sin x} $
C) $ \frac{1}{\tan x} $
D) $ \cos x $
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Answer:
Correct Answer: A
Solution:
[a] In first case $ \tan \theta =\frac{Bv}{B_{H}} $ Second case $ \tan \theta ‘=\frac{Bv}{B_{H}\cos x} $ From Eqs. (i) and (ii), $ \frac{\tan \theta ‘}{\tan \theta }=\frac{1}{\cos x} $
BETA
