Magnetic Effects Of Current Question 245

Question: A thin bar magnet of length 2 L is bent at the mid-point so that the angle between them is $ 60{}^\circ $ . The new length of the magnet is

Options:

A) $ \sqrt{2},L $

B) $ \sqrt{3},L $

C) $ 2,L $

D) $ L $

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Answer:

Correct Answer: D

Solution:

[d] When the magnet is bent, the length of the magnet is: $ AC=AB+BC $ $ =L\sin \frac{\theta }{2}+L\sin \frac{\theta }{2} $ $ =2L\sin (\theta /2)=2L,sin(60{}^\circ /2) $ $ =2L\sin 30{}^\circ =L $